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Sample Solutions
AP Physics B

Hecht:  Physics with Algebra/Trig


Chapter 12: 2004 Set 11

Problems
SHM pg 436
#
5,6,8,17,18,22

Problems

#5 A body oscillates in SHM according to the equation: x = 5.0 cos (0.40t + 0.10)

A = 5.0 m

2pf = 0.40
f = 0.40/2p
f = 0.0637 hz

phase = 0.10 radians

x = 5.0 cos [0.40(2) + 0.10]
x = 3.11 m
(remember that your calculator must be in radians!]

#6  A body oscillates in SHM according to the equation: x = 8.0 cos (1.2t + 0.4)

A = 8.0 m

2pf = 1.2
f = 1.2/2p
f = 0.191 hz

T = 1 / f
T = 5.24 seconds

#8  Given: v = 1.57 m/sec; A = 0.5 mm = 0.0005 meters.  Set v = A(2pf) and solve for the frequency, f.

v= A(2pf)
1.57 = 0.0005 (2pf)
f = 1.57 / 0.0010p
f = 1.57 / 0.0010p
f = 500 hz

#17  Given: m = 0.20 grams = 0.0002 kg; f = 18 hz.  Use the equations T = 1 / f and  T = 2p squareroot.gif (935 bytes)(m/k) and solve for k.

1/18 = 2p squareroot.gif (935 bytes)(0.0002/k)
k = 2.56 N/m

#18 Given: m = 5 kg, k = 50 N/m, A = 10 cm = 0.10 m.  Use conservation of energy, PEe = KE and solve for v.

KE = PEe
½mv2 = ½kA2
v = A (k / m)
v = 0.10  (50 / 5)
v = 0.316 m/sec

#22 At 5.0 cm, the energy is both KE and PEe.  By conservation of energy, PEe10 cm = (KE + PEe )5 cm

PEe = KE + PEe
½(50)(0.10)2 = ½(50)(0.05)2 + ½(5)v2
0.25 = 0.0625 + 2.5v2
0.1875 = 2.5 v2
v = 0.274 m/sec

 




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